- #1
SherBear
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Homework Statement
We have a person pulling on a string or rope in the negative y negative x quadrant (call it left) this person is called Wesson, they have a force of 300N at 30°
Same situation but pulling the other way, positive y and positive x quadrant (call it right), this person is called Canola, they have a force of 200N at 30°
The third person pulling is the boss called Olive, they have a force of 250N at 60°
What I'm seeking is this: What is the magnitude and direction of the force the boss needs to apply to make the system at equilibrium?
Homework Equations
First make a FBD then..
I have the sum of Fx = -tw + tc + to = 0
Pithagoram's theory
arc tan...Tan-1 (Fy/Fx)
The Attempt at a Solution
from the sum of Fx I have = -300N sin 30° + 200N sin 30° + 250N sin 60°
-150 + 100 + 216.50=
Fx=166.5
To get the magnitude I'm using pithagorm's theorm
so I have sqrt 166.5^2 + 0 (because the sum in the y dir is zero)
magnitue= 52.17N
To get the direction I have
Tan -1 (0 / 166.5N) = 0 N = Direction
Am I on the money or way off base?