2002 ap physics c free response #1 question

Click For Summary
SUMMARY

The discussion revolves around solving a 2002 AP Physics C free response question involving a collision between a car and an object. The car, with a mass of 1000 kg and an initial speed of 12 m/s, collides inelastically with an object of mass M. The post-collision speed is defined by the equation v = 8/(1 + 5t). The participant initially calculated the mass M incorrectly as 1400 kg but later corrected it to 500 kg using the conservation of momentum. The discussion also touches on deriving expressions for position and resisting force after the collision.

PREREQUISITES
  • Understanding of conservation of momentum in inelastic collisions
  • Familiarity with calculus for integrating velocity functions
  • Knowledge of Newton's second law (F = ma)
  • Ability to manipulate algebraic expressions and solve equations
NEXT STEPS
  • Study the derivation of position functions from velocity equations
  • Learn about impulse and its calculation in physics
  • Explore the concept of resisting forces in motion
  • Review previous AP Physics C free response questions for practice
USEFUL FOR

Students preparing for the AP Physics C exam, educators teaching physics concepts, and anyone interested in mastering collision dynamics and related calculations.

dlau
Messages
2
Reaction score
0
hello, in lieu of the upcoming ap exam, I have been studying old free response questions from ap exams. I have a question about this one

A crash test car of mass 1000kg moving at constant speed of 12m/s collides completely inelastically with an object of mass M at time t=0. the object was initially at rest. the speed v in m/s of the car-object system after the collision is given as a function of time t in seconds by the expression

v=8/(1+5t)

(a)calculate the mass of the object
(b) assuming the initial position of x=0, determine an expression for the car object system after the collision as a function of time t
(c)determine an expression for the resisting force on the car-object system after the collision as a function of time t.
(d) determine the impulse delivered to the car-object system from t=0 to t=2s

I am currently doing A, and I came up with:

m1v1=(m1+m2)v2 <= (law of conservation)
(1,000)(12)=(1000+M)8

I got the 8 by plugging t=0 into v=8/(1+5t)

so M=1400KG? For some reason it does not seem right ...
 
Physics news on Phys.org
dlau said:
so M=1400KG? For some reason it does not seem right ...
It's not. Your method is correct, but you must have made an arithmetic error.
 
dlau said:
hmm, alright, I got 500KG for the part a.
Right.

for part b, is it just integrating the v=8/(1+5t)?
Yep.

it looks like I am stuck on part c ...
Think F = ma. You have v(t). Find a.
 
  • Like
Likes Mammy07
thanks! I solved it!
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
Replies
12
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 9 ·
Replies
9
Views
5K
Replies
2
Views
18K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 38 ·
2
Replies
38
Views
4K
Replies
7
Views
2K