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## Homework Statement

#24

https://aapt.org/physicsteam/2010/upload/2009_F-maSolutions.pdf

## Homework Equations

T = rfsinθ

## The Attempt at a Solution

FBD:

Axes: (along the incline is x), perpendicular to that is y:

Down: mgcosθ

Up: N

Right: mgsinθ

Left: Ff (friction)

If the box is to tip over, it will rotate around one vertex, namely the bottom right.

We choose that as PoR and do net torque.

(b/2)mgcosθ = Torque, isn't that the only torque?

Or is it:

b/2mgcosθ = aμmgcosθ

If the box isn't slipping down the plane, then

Ff = mgsinθ

μmgcosθ = mgsinθ

tanθ = μ

I don't really know what to do beyond that.