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## Homework Statement

A rocket is fired at a speed of 75.0 m/s from ground level, at an angle of 55.9° above the horizontal. The rocket is fired toward an 11.0 m high wall, which is located 29.5 m away. The rocket attains its launch speed in a negligibly short period of time, after which its engines shut down and the rocket coasts. By how much does the rocket clear the top of the wall?

## Homework Equations

Eight Kinematic Equations

## The Attempt at a Solution

Voy = VoSin55.9 = 75 sin 55.9 = 62.1045251

v^2 = Vy^2 + Vx^2

V^2 = 62.1^2 + 29.5^2

Definitely not right, I just can't seem to figure it out