A rocket is fired at a speed of 75.0 m/s from ground level, at an angle of 55.9° above the horizontal. The rocket is fired toward an 11.0 m high wall, which is located 29.5 m away. The rocket attains its launch speed in a negligibly short period of time, after which its engines shut down and the rocket coasts. By how much does the rocket clear the top of the wall?
Eight Kinematic Equations
The Attempt at a Solution
Voy = VoSin55.9 = 75 sin 55.9 = 62.1045251
v^2 = Vy^2 + Vx^2
V^2 = 62.1^2 + 29.5^2
Definitely not right, I just can't seem to figure it out