2i-6i1+4i2=0 3i+4i1-9i2=0 5i-3i1-5i2=0 check i1

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Discussion Overview

The discussion revolves around solving a system of equations related to electrical currents in a circuit using Kirchhoff's Voltage Law (KVL) and matrix methods. Participants explore the implications of assumed current directions and the inclusion of voltage sources in their equations.

Discussion Character

  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant presents three equations derived from a circuit diagram and seeks to solve for the current i1 using matrix methods, expressing confusion over the results obtained.
  • Another participant notes that the system of equations does not account for a 2V battery present in the circuit, suggesting this may be a source of error.
  • A participant references Kirchhoff's Voltage Law (KVL) and questions the absence of an electromotive force (emf) in their equations, despite having a voltage source in the circuit.
  • One participant proposes a voltage equation based on the resistors in the circuit, indicating how to relate the currents to the supply voltage.
  • Another participant agrees with the previous voltage equation but emphasizes the importance of proper sign conventions when applying KVL around the loop.
  • A later reply suggests that the currents must depend on the supplied voltage and encourages the inclusion of voltage in the equations, providing a total current value derived from the supply voltage.

Areas of Agreement / Disagreement

Participants express differing views on the correct formulation of the equations, particularly regarding the inclusion of the voltage source and the application of KVL. There is no consensus on the correct approach to solving the equations.

Contextual Notes

Some participants mention confusion regarding the proper application of KVL and the inclusion of voltage sources in their equations. There are unresolved assumptions about the circuit configuration and the effects of the voltage source on the current calculations.

Who May Find This Useful

This discussion may be useful for students or individuals studying circuit analysis, particularly those interested in applying Kirchhoff's laws and matrix methods to solve electrical circuit problems.

ritzmax72
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In this diagram(made at last) if i assume the curren direction as shown, I get 3 equations:
2i-6i1+4i2=0
3i+4i1-9i2=0
5i-3i1-5i2=0
check i1 is i subscript 1.(i don't know how to write subscript).
if i put in matrix form( i want to solve via matrix method only).
i am getting i=0 i1=0 i2=0, used cramer,s rule.
also tried row echeleon form. but didn't get any solution.
am i right in giving curret direction? is there any wrong convection? am i forgetting any rule.
in book the author has taken x y z(x and y in leftmost two branch AND Z IN MIDDLE branch).
he gets a good matrix with 0,0,2 in right hand side after "=" sign.(i m not writing those equations)
tell me what is the wrong with me?please neede within 1 day!
 
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I'm sorry but that diagram is hard to read. I can tell you though that the system of equations represent voltages in a loop that sum to zero. Your diagram shows a 2v battery and your system of equations do not show this voltage.

That maybe one of the problems...
 


That means i should write
equation=2 volts?
But kvl says "the algebric sum of the products of currents and resistances in each of the conductor in any closed path(mesh) in a network plus the algebric sum of the emfs in that path is zero"
taking this def. Along the rhombhus path. I don't get any emf. There's only one emf i.e outermost.
 


The voltages across either two of the outer series resistors equals the supply voltage.

So, you would get I1 * 1 + (I1 - I2) * 2 = 2 ...Where the final 2 is the supply voltage
 


Yes u have done right thing.
I1*1-(I1-I2)=2. I UNDERSTAND.
BUT WHEN WE USE KVL, THEN WE CHOOSE A LOOP.THEN WE TRAVEL AROUND THAT LOOP ADD THE VOLTAGE DROPS. WE TAKE PROPER SIGN CONVENTION. THAT IS IF WE TRAVEL IN DIRECTION OF ASSUMED CURRENT THEN WE TAKE VOLTAGE DROP AS NEGATIVE AND VICE VERSA. TAKING THESE THINGS AND THREE LOOPS I HAVE WRITTEN 3 EQUATIONS. EACH EQUALS TO 0. SO I DON'T GET ANY RESULT. WHAT WRONG HAVE I DONE?
 


You haven't done anything wrong, but the currents in the circuit must depend on the supplied voltage, so you have to include equations that have this voltage in them.

There are two resistors at the top and two at the bottom that are across 2 volts. So you can make equations using that information.

The total current from the 2 V supply in your circuit is 1.068 amps.
 


Fine. Thanks all.
 

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