2nd order differential equation

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Homework Help Overview

The discussion revolves around solving a second-order differential equation of the form y'' + 16y = 3.36, which is related to a spring problem. Participants are exploring the method of undetermined coefficients to find a particular solution in addition to the homogeneous solution.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss finding the characteristic equation and the homogeneous solution, with some suggesting the need for a particular solution. There is a focus on the rationale behind choosing a trial solution of the form yp = A versus yp = Ax, with questions about the appropriateness of these choices.

Discussion Status

The discussion includes attempts to clarify the method of finding the particular solution, with some participants providing guidance on trial solutions. There is an acknowledgment of the need to ensure the trial function is not a multiple of the homogeneous solution. Multiple interpretations regarding the choice of trial functions are being explored.

Contextual Notes

Participants reference a course in differential equations, suggesting that the problem is situated within a broader educational context that includes methods such as undetermined coefficients.

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Homework Statement



y''+16y=3.36

This is actually part of a spring question I'm attempting at the moment, and I'm having a mental blank on how to deal with the 3.36.

Homework Equations



n/a

The Attempt at a Solution



I've found the characteristic equation and solution based from that;
c_1 cos(4x) + c_2 sin(4x)
but the answer is
c_1 cos(4x) + c_2 sin(4x) + 0.21
 
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Remember: The general solution to any linear non-homogeneous differential eq. is equal to the soln. to the homogeneous sq. plus the particular soln. to the non-homogeneous eq.
What is your characteristic eq. here?
 
You found the homogeneous solution. You need to find the particular solution. Try substituting a trial solution of the form yp=A and solving for A.
 
vela said:
You found the homogeneous solution. You need to find the particular solution. Try substituting a trial solution of the form yp=A and solving for A.

y_p = A <br /> so doing that I get A = 0.21, which gives me the correct solution.<br /> <br /> thanks.
 
However do you know the rationale for choosing trail function as A instead of A x
 
yep. so it isn't a multiple of the homogenous solution. I did a course of DE's a while ago, I just forgot what to do in this case.
 
icystrike said:
However do you know the rationale for choosing trail function as A instead of A x
If you had tried Ax, then (Ax)''= 0 so the equation would have been 16Ax= 3.36. The left side has an "x" and the right side doesn't. May I ask why you are doing this problem? I would imagine it is because you are taking a course in differential equations but I cannot imagine you having a homework problem like this if you are not in a chapter of your textbook that has a detailed description of "Undetermined Coefficients" as this method is called.
 

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