How Do You Solve a 2nd Order Inhomogeneous ODE with Given Initial Conditions?

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The discussion focuses on solving the second-order inhomogeneous ordinary differential equation (ODE) given by d²y/dx² + 3 dy/dx + 2y = 20cos(2x) with initial conditions y(0) = 1 and y'(0) = 0. The complementary function is identified as y = Ae^(-x) + Be^(-2x). Participants suggest using the method of undetermined coefficients or Variation of Parameters to find the particular integral, proposing yp = Ccos(2x) + Dsin(2x) as a suitable form for the particular solution.

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1. Using the complementary function and particular integral method find the solutio of the differential equation.

d2y/dx^2 + 3 dy/dx +2y = 20cos2x

Which satisfies y(0) = 1 y'(0) = 0



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The Attempt at a Solution

 
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there are different ways to solve this differential equation.
I know you can solve it with the method of undetermined coefficients OR Variation of Parameters.
 
I have already found the complementary function to be:

y = Ae^(-t) + Be(-2t)

Im just not sure how to find the particular integral!
 
Try yp = Ccos(2x) + Dsin(2x) for your particular solution.

Minor note: The independent variable should be x, not t, since x is the independent variable in your differential equation.
 

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