2nd order ODE - Show solution by substitution

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Homework Help Overview

The problem involves demonstrating that a specific integral expression for y(t) serves as a particular solution to a second-order ordinary differential equation (ODE) involving a constant w and a function f(t). The context is rooted in applied partial differential equations and Fourier series.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the necessity of differentiating the integral expression for y(t) and the challenges posed by the lack of information about f(s). There is mention of integration by parts and its limitations in this context. The application of the fundamental theorem of calculus is also questioned due to the additional sine term in the integrand.

Discussion Status

Some participants have provided guidance on using Leibniz's rule for differentiation, suggesting that this approach may be more appropriate than integration by parts. There is acknowledgment of unfamiliarity with certain rules, indicating a productive exchange of ideas.

Contextual Notes

The original poster expresses frustration over the complexity of the problem and the iterative nature of integration by parts, highlighting the need for more information about the function f(s) to progress. The problem is sourced from a specific textbook, which may imply certain constraints or expectations regarding the solution approach.

wxstall
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Homework Statement



Show that

y(t) = (1/w) ∫[0,t] f(s)*sin(w(t-s)) ds

is a particular solution to

y'' +w2 y = f(t)where w is a constant.

The Attempt at a Solution



After wasting several pages of paper I have made virtually no progress. Obviously, substitution suggests you plug in y(t), differentiate it twice for the first term, and somehow arrive at f(t) = f(t). However, without more information about f(s), it seems impossible. Integration by parts on y(t) will result in another integral which in turn must be integrated by parts...and so on infinitely many times. Therefore integration by parts of the solution y(t) is not an option.

I have considered that this could be an application of the fundamental theorem of calculus, but with an additional sine term that also depends on t in the integrand, it seems not not apply (at least not in a way I am familiar with).This is a problem from Richard Haberman's text: Applied PDE with Fourier Series and Boundary Value Problems.

Any ideas/advice would be much appreciated.
Thank you
 
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wxstall said:

Homework Statement



Show that

y(t) = (1/w) ∫[0,t] f(s)*sin(w(t-s)) ds

is a particular solution to

y'' +w2 y = f(t)


where w is a constant.

The Attempt at a Solution



After wasting several pages of paper I have made virtually no progress. Obviously, substitution suggests you plug in y(t), differentiate it twice for the first term, and somehow arrive at f(t) = f(t). However, without more information about f(s), it seems impossible. Integration by parts on y(t) will result in another integral which in turn must be integrated by parts...and so on infinitely many times. Therefore integration by parts of the solution y(t) is not an option.

I have considered that this could be an application of the fundamental theorem of calculus, but with an additional sine term that also depends on t in the integrand, it seems not not apply (at least not in a way I am familiar with).


This is a problem from Richard Haberman's text: Applied PDE with Fourier Series and Boundary Value Problems.

Any ideas/advice would be much appreciated.
Thank you

You don't need to integrate anything. You need to differentiate using Leibnitz's rule. There are several forms. You will find this form useful:$$
\frac d {dt} \int_0^t g(s,t)\, ds = \int_0^t \frac {\partial g(s,t)}{\partial t}\, ds + g(t,t)$$
 
So as I suspected, it's some rule that I was unfamiliar with. Thanks for the help!
 

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