3 blocks on a frictionless surface

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Homework Help Overview

The problem involves three blocks of different masses on a frictionless surface, subjected to a force. The original poster seeks to determine the force exerted by one block on another, specifically the force the 2.16 kg block exerts on the 2.87 kg block.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss calculating acceleration and using it to find forces, with some questioning the method of isolating forces acting on individual blocks. There is also mention of drawing Free Body Diagrams to clarify forces.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem and the relationships between the forces acting on the blocks. Some guidance has been provided regarding the need for Free Body Diagrams, but no consensus has been reached on the correct approach for the first part of the problem.

Contextual Notes

Participants note confusion regarding the application of Newton's laws and the calculation of net forces, indicating a potential misunderstanding of the problem setup. There is also mention of a second part of the problem that has been resolved by one participant.

talaroue
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Homework Statement



Blocks with masses of 0.54 kg, 2.16 kg, and 2.87 kg are lined up in a row on a frictionless table. All three are pushed forward by a 13.8 N force applied to the 1 kg block. How much force does the 2.16 kg block exert on the 2.87 kg block?



Homework Equations



Fnet=ma

The Attempt at a Solution


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I thought all I had to do was calculate the acceleration and then multiply by the mass of the second block?
 
There is a second part of the problem that I got right...
How much force does the 2.16 kg block exert on the 0.54 kg block?
I found the acceleration which is 13.8/5.57=2.48 m/s^2 then i took that and mutliplied it by .54 kg that gave me N then I subtracted that N from the orginal 13.8...but it doesn't work for the first part why?
 
talaroue said:
Blocks with masses of 0.54 kg, 2.16 kg, and 2.87 kg are lined up in a row on a frictionless table. All three are pushed forward by a 13.8 N force applied to the 1 kg block. How much force does the 2.16 kg block exert on the 2.87 kg block?

I thought all I had to do was calculate the acceleration and then multiply by the mass of the second block?
No, this will give you the net force acting on the 2nd block, not the force of block 2 on block 3. Instead, once you calculate the acceleration, you must draw a Free Body Diagram (FBD) which isolates the last (2.87 kg) block, identify the forces acting on that block, and apply Newton's laws to that block to solve for the force of block 2 on block 3.

talaroue said:
There is a second part of the problem that I got right...
How much force does the 2.16 kg block exert on the 0.54 kg block?
I found the acceleration which is 13.8/5.57=2.48 m/s^2
Correct.
then i took that and mutliplied it by .54 kg that gave me N
no it didn't, it gave you the net force acting on block 1
then I subtracted that N from the orginal 13.8...but it doesn't work for the first part why?
you mean you subtracted the net force from the 13.8 to get the force of block 2 on block 1.
 
Yeah I meant I subtracted the net force from 13.8. I got the first one but not the second one...hmmmm i think I will meet with my professor and ask him what i should have done. thank you guys for your help.
 

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