3-dimensional center of mass problem

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SUMMARY

The discussion focuses on calculating the center of mass of the ammonia (NH3) molecule, where the three hydrogen (H) atoms form an equilateral triangle and the nitrogen (N) atom is positioned above this triangle. The center of the triangle is located 9.40x10-11 m from each hydrogen atom, while the nitrogen atom is 10.4x10-11 m away from the hydrogen atoms. The nitrogen-to-hydrogen atomic mass ratio is 13.9, which is essential for determining the overall center of mass using the equation Rcom=(1/M)(sum of MiRi from i=1 to n).

PREREQUISITES
  • Understanding of three-dimensional coordinate systems
  • Familiarity with the concept of center of mass
  • Knowledge of atomic mass ratios
  • Proficiency in applying the center of mass formula Rcom=(1/M)(sum of MiRi from i=1 to n)
NEXT STEPS
  • Research the concept of symmetry in molecular structures
  • Learn about the application of the center of mass in three-dimensional physics problems
  • Study the implications of atomic mass ratios in molecular geometry
  • Explore methods for simplifying complex three-dimensional problems
USEFUL FOR

Students studying chemistry or physics, particularly those focusing on molecular geometry and center of mass calculations, as well as educators looking for examples of three-dimensional problem-solving in molecular structures.

brendan3eb
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Homework Statement


In the ammonia (NH3) molecule, the three hydrogen (H) atoms form an equilateral triangle; the center of the triangle is 9.40x10^(-11) m from each hydrogen atom. The nitrogen (N) atom is at the apex of a pyramid, with the three hydrogen atoms forming the base. The nitrogen-to-hydrogen atomic mass ratio is 13.9, and the nitrogen-to-hydrogen distance is 10.4x10^(-11) m. Locate the center of the molecule relative to the nitrogen atom.


Homework Equations


Rcom=(1/M)(sum of MiRi from i=1 to n)


The Attempt at a Solution


I have read through the problem several times, and I started to try and solve the problem by just figuring out the three-dimensional coordinates, but it seems a bit odd for the book to give such a tedious problem. Is there some sort of symmetry or way of re-drawing the problem to eliminate the z-axis that I am not picking up on, or do I really need to use all three axis to figure out the answer?
 
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I think you're allowed to treat the 3 H atoms as one mass focused in the centre of the 3 H atoms. This would have a mass of triple one H atom, and it would be directly under the N atom. I think.
 

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