Need help finding center of mass of a molecule.

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Homework Help Overview

The discussion revolves around finding the center of mass of a nitric acid (HNO3) molecule, treating its atoms as point particles. Participants are exploring the necessary calculations and considerations involved in determining the center of mass based on given dimensions and atomic masses.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the formula for calculating the center of mass and question how to apply it to the specific atomic masses and distances. There is uncertainty regarding the y-axis and its relevance in the calculations, as well as the interpretation of coordinates for the atoms.

Discussion Status

The discussion is active, with participants providing various interpretations of the coordinate system and the distances involved. Some guidance has been offered regarding the need to clarify the coordinates of the atoms, and there is an ongoing exploration of how to incorporate the masses and distances into the center of mass calculations.

Contextual Notes

There are conflicting views on the presence and significance of the y-axis in the problem setup. Participants are also addressing the implications of using certain distances and angles in their calculations, indicating a need for clarity on the geometric arrangement of the molecule.

Sneakatone
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Figure below shows the shape of a nitric acid (HNO3)molecule and its dimensions. Treating the atoms as particles, findthe center of mass of this molecule.

a)I know that xcm=m1x1+m2x1+.../Total mass.
The total mass in this case is 63 but based on the picture I don't know which mass I should plug in for the x values.

b)ycm=0 because there is no y axis.
 

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The mass for every x value is the mass of the atom at that position.

What do you mean by "there is no y axis"?
 
so you mean for the 1st one 0.1 nm*1(mass of hydrogen)+0.141nm*16(mass of oxygen)/63?

there's no y-axis means there isn't an angle that goes 90 degrees.
 
Sneakatone said:
so you mean for the 1st one 0.1 nm*1(mass of hydrogen)+0.141nm*16(mass of oxygen)/63?

What about nitrogen?

there's no y-axis means there isn't an angle that goes 90 degrees.

There is a Y axis. And it is even clearly labeled as such.
 
a) 0.1 nm*1(mass of hydrogen)+0.141nm*16(mass of oxygen)+0.282*14(mass of nitrogen)/63
(should I use the two lengths by nitrogen 0.141nm+0.141nm or just 0.141nm*14g)?

b) the y-axis has a length of zero so when multiplied with the mass of oxygen it becomes zero.
 
Sneakatone said:
a) 0.1 nm*1(mass of hydrogen)+0.141nm*16(mass of oxygen)+0.282*14(mass of nitrogen)/63
(should I use the two lengths by nitrogen 0.141nm+0.141nm or just 0.141nm*14g)?

What are the distances measured from?

b) the y-axis has a length of zero so when multiplied with the mass of oxygen it becomes zero.

An axis cannot have a length of zero. An axis is infinite by definition.
 
the distances are measures from the 130 degree angle.
 
And I would think the distances are measured from the origin of the coordinate system, which is at the intersection of the X and Y axes. I advise that before going further, you should find out the coordinates of all the atoms in the molecule.
 
if the origin is O where the y-axis is labeled then coordinates are ,H(0,-0.1),N(0,0.141)
 
  • #10
The molecule has 5 atoms.
 
  • #11
H(-0.1,0),o(0,0),n(0.141,0), o(0.2,0.12),o(0.2,-0.12)
 
  • #12
I assume the first number in all the pair is the Y coordinate, correct? It is unusual, but permissible. The first three pairs are OK. The last two, however, are completely wrong.
 
  • #13
fot the last 2 I did .141cos65 ans added to .141
 
  • #14
I am sorry, I have misread your message. The coordinates are correct. Now you have all the X's and all the Y's to compute the c. m.
 
  • #15
thanks a lot! , I plugged em into the equation and ended up with 0.131 for x and 0 for y.
 

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