3D Quantum harmonic Oscillator

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
6 replies · 5K views
c299792458
Messages
67
Reaction score
0

Homework Statement


What are the stationary states of an isotropic 3D quantum harmonic oscillator in a potential [tex]U(x,y,z) = {1\over2}m\omega^2 (x^2+y^2+z^2)[/tex] in the form [tex]\psi(x,y,z)=f(x)g(y)h(z)[/tex] and how many linearly independent states have energy [tex]E=({3\over 2}+n)\hbar\omega[/tex]?


Homework Equations



See above.

The Attempt at a Solution


The solution of a HO in 1D, say the x-direction, is [tex]c H_n e^{\sqrt{m\omega\over\hbar}x}[/tex] where [tex]H_n[/tex] is the [tex]nth[/tex] Hermite polynomial. So I am guessing [tex]\psi = c^3 H_n^3 e^{{m\omega\over\hbar}(x^2+y^2+z^2)}[/tex]. I don't quit understand how to count L.I. states, though. I am guessing the number of combinations of [tex]n_x,n_y,n_z[/tex] such that [tex]n_x+n_y+n_z=n[/tex]? Please help! Thanks
 
Physics news on Phys.org
c299792458 said:

Homework Statement


What are the stationary states of an isotropic 3D quantum harmonic oscillator in a potential [tex]U(x,y,z) = {1\over2}m\omega^2 (x^2+y^2+z^2)[/tex] in the form [tex]\psi(x,y,z)=f(x)g(y)h(z)[/tex] and how many linearly independent states have energy [tex]E=({3\over 2}+n)\hbar\omega[/tex]?


Homework Equations



See above.

The Attempt at a Solution


The solution of a HO in 1D, say the x-direction, is [tex]c H_n e^{\sqrt{m\omega\over\hbar}x}[/tex] where [tex]H_n[/tex] is the [tex]nth[/tex] Hermite polynomial.
That's not quite right.
So I am guessing [tex]\psi = c^3 H_n^3 e^{{m\omega\over\hbar}(x^2+y^2+z^2)}[/tex].
Decent guess. Try plugging [itex]\psi(x,y,z)[/itex] into the Schrödinger equation. You should find the equation separates, so you can solve it.
I don't quit understand how to count L.I. states, though. I am guessing the number of combinations of [tex]n_x,n_y,n_z[/tex] such that [tex]n_x+n_y+n_z=n[/tex]? Please help! Thanks
Yes, that's correct.
 
Thanks, vela. So is [tex]\psi=cH_{n_x}H_{n_y}H_{n_z}e^{{m\omega\over\hbar}{(x^2+y^2+z^2)}}[/tex], where c is some normalization constant?
 
Ah, thanks. Is the argument [tex]\sqrt{m\omega\over\hbar}x_i[/tex], where [tex]x_i\in\{x,y,z\}[/tex]?