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A 20 kg sphere is at the origin and a 10 kg sphere is at (x,y) = (20,0

  1. Mar 26, 2014 #1
    1. The problem statement, all variables and given/known data

    a 20 kg sphere is at the origin and a 10 kg sphere is at (x,y) = (20,0). at what point or points could you place a small mass such that the net gravitational force on it due to the spheres is zero?

    2. Relevant equations

    g=GM/r^2

    3. The attempt at a solution

    Can not figure out how to plug into the equation
     
  2. jcsd
  3. Mar 26, 2014 #2
    $$F = G \frac {m_{1}m_{2}}{r^2}$$

    Might be a better option.

    ##r## is the radius between the two masses.
     
  4. Mar 26, 2014 #3
    Thank you! How would I go about plugging my information into the equation?
    I'm extremely new to physics and the textbook lacks information on solving this problem
     
  5. Mar 26, 2014 #4
    Well, you know that your forces have to cancel out.

    This means you can set your forces equal. The book tells you that you can go ahead and ignore the mass of the particle that you want to set in between them, so you'll have two equations.

    $$F = G \frac {m_{1}}{{r_{1}}^2}$$

    and $$F = G \frac {m_{2}}{{r_{2}}^2}$$

    So you can simplify that using simple algebra pretty easily if you set those equation equal to each other. This will give you a relationship between ##r_{1}## and ##r_{2}##.

    You'll need one more equation to solve for the two unknowns. Just remember that your two radii have to add up to be the original radius between the two spheres. From there you've got 2 equations and 2 unknowns, and you're set!
     
  6. Mar 26, 2014 #5
    Thank you very much!
    What does G equal?

    And for the radius would I divide the distance by 2?
     
  7. Mar 26, 2014 #6
    No. r1 and r2 are the quantities you're trying to find, remember? They are the unknowns of your problem. If you could just divide the distance by two there would be no need to solve the problem to begin with...
     
  8. Mar 26, 2014 #7
    G = 6.67 x 10^(-11) N m^2/kg^2, but you don't need to know that in order to solve that problem. Your approach ought to be 1st solve the algebraic equation and only then plug in the data. That should always be your approach. Algebra is your friend.
     
  9. Mar 26, 2014 #8
    Okay, now I'm lost again. If I don't need to know what G is then what equation should I be using?
     
  10. Mar 26, 2014 #9

    G is a constant. It would end up cancelling out. Conceptually, there is nothing to this problem once you have the two force equations set equal to each other. It is simply algebra.

    You need to examine this problem a little more closely and figure out how and what you are solving for.

    You will have two unknowns, which means you will need at least two defining equations for your parameters. My earlier post gave you hints on how to find both.
     
  11. Mar 26, 2014 #10
    Use the equation provided in post # 2 (twice - once for each force).

    Solve the problem algebraically and then you will understand why you don't need to know the value of G.
     
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