A Banked Turn With Friction- min and max velocity

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SUMMARY

The discussion focuses on calculating the maximum and minimum speeds of a car navigating a banked turn with a 25º angle, a radius of 50 meters, and a coefficient of static friction of 0.35. The maximum speed (v_max) to prevent slipping upwards is determined to be 21.6 m/s, while the minimum speed (v_min) to prevent slipping downwards is calculated as 8.25 m/s. The equations used include centripetal force and frictional force components, specifically F_net = Nsinθ ± fcosθ = (tanθ ± µ / 1 - tanθ)mg. The calculations require clarification on the derivation of the formulas used.

PREREQUISITES
  • Understanding of centripetal force and its application in circular motion
  • Knowledge of static friction and its role in preventing slipping
  • Familiarity with trigonometric functions, particularly tangent
  • Ability to manipulate and solve equations involving forces and motion
NEXT STEPS
  • Review the derivation of centripetal force equations in circular motion
  • Study the effects of friction on inclined planes and banked curves
  • Explore the relationship between angle of banking and speed in vehicular dynamics
  • Practice solving similar problems involving forces on inclined surfaces
USEFUL FOR

Students in physics or engineering, automotive engineers, and anyone interested in the dynamics of vehicles on banked turns.

mmoadi
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Homework Statement



A car drives through a turn with a bank angled at 25º according to horizontal floor. How much does the highest speed of the car have to be to prevent the car from slipping on the slope upwards? How much does the smallest speed of the car have to be to prevent the car from slipping on the slope downwards? Radius of the turn is 50m and the coefficient of static friction is 0, 35.

Homework Equations



F= mg
f= µN
F_centripetial= mv² / r

The Attempt at a Solution



For the max speed (v_max) that you can safely use for car to not slip up:

F_net= Nsinθ + fcosθ= (tanθ+µ / 1-tanθ)mg

F_net = F_centripetal
v_max= sqrt((tanθ+µ / 1-tanθ)rg)= 21.6 m/s

For the min speed (v_min) that you can safely use for car not to slip down:

F_net= Nsinθ - fcosθ= (tanθ-µ / 1-tanθ)mg

F_net = F_centripetal
v_max= sqrt((tanθ-µ / 1-tanθ)rg)= 8.25 m/s

Are my calculations correct?
 
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Show your derivation a bit more detailed. Your formulas are not correct now. What do you mean on

(tanθ+µ / 1-tanθ) ? tanθ cancels.

ehild
ehild
 
I would really like to know if my approach resolving this problem is correct?
thank you!
 

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