A block of mass 100 kg is being moved steadily by pulling on a rope at

In summary: The coefficient of friction is calculated by dividing the force of friction by the normal force.So, if the normal force is 980N, and the force of friction is 60N, the coefficient of friction is 0.0612.In summary, to find the coefficient of friction in this scenario, you need to calculate the force of gravity on the block (100 x 9.8 = 980 N) and the vertical component of tension (120 x sin(30) = 60N). Then, divide the force of friction by the normal force (60/980) to get the coefficient of friction (0.0612). This is different from the given answer of 0.113, suggesting that there may be
  • #1
jigoku_snow
15
0

Homework Statement

a block of mass 100 kg is being moved steadily by pulling on a rope attached to the block making an angle of 30 degree with the horizontal. if the tension of the rope is 120 N, what is the coefficient of friction?

Homework Equations


T- Ff = ma
F= μR

The Attempt at a Solution


R= mg cos x = 850 N
mg sin x = 490 N
a = 0, F= Ff
Ff = 120 N
F= μR
120= μ(850)
μ= 0.141
* ( answer given μ= 0.113. where is my mistake?)
 
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  • #2


jigoku_snow said:

Homework Statement




a block of mass 100 kg is being moved steadily by pulling on a rope attached to the block making an angle of 30 degree with the horizontal. if the tension of the rope is 120 N, what is the coefficient of friction?

Homework Equations


T- Ff = ma
F= μR


The Attempt at a Solution


R= mg cos x = 850 N
mg sin x = 490 N
a = 0, F= Ff
Ff = 120 N
F= μR
120= μ(850)
μ= 0.141
* ( answer given μ= 0.113. where is my mistake?)

Not sure how/why you are doing any of those calculations. It always helps to say what you are about to do, then show the calculation.

Like for example:
Calculating force of gravity on the block : 100 x 9.8 = 980 N

Calculating vertical component of Tension: 120 x sin(30) = 60N

and what ever else you think is appropriate.

You then connect what you are calculating to give the answer you are after. A diagram can help.
 

1. How much force is required to move the block?

The amount of force required to move the block depends on the coefficient of friction between the block and the surface it is being moved on. The higher the coefficient of friction, the more force is needed to move the block. Other factors such as the angle of the rope and the mass of the block also play a role.

2. What happens if the force applied is greater than the force of friction?

If the force applied is greater than the force of friction, the block will accelerate and move at a faster rate. However, if the force applied is too great, the block may start to slide or topple over.

3. Can the block be moved without using a rope?

Yes, the block can be moved by using other methods such as pushing or using other objects to apply force. The amount of force needed will still depend on the coefficient of friction and other factors.

4. Will the mass of the block affect the amount of force needed to move it?

Yes, the mass of the block will affect the amount of force needed to move it. The greater the mass, the more force is required to overcome the force of friction and move the block.

5. How does the angle of the rope affect the force needed to move the block?

The angle of the rope affects the force needed to move the block because it changes the direction of the force being applied. The greater the angle, the more the force is directed towards pulling the block in a horizontal direction, making it easier to move. However, if the angle becomes too steep, the force may become too vertical and not enough to overcome the force of friction.

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