A coil of wire is connected to an uncharged capacitor in a magnetic field

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SUMMARY

The discussion centers on calculating the voltage across an uncharged 1.0 microFarad capacitor connected to a 10-turn coil of wire with a diameter of 1.0 cm and a resistance of 0.20 ohms, which is pulled from a 1.0 mT magnetic field. The total magnetic flux through the coil is calculated to be 7.85 x 10^-7 Wb. The induced electromotive force (emf) is determined using the relationship between the change in magnetic flux and time, although the time variable is not provided in the problem. The voltage across the capacitor is initially 0 V, as it is uncharged.

PREREQUISITES
  • Understanding of electromagnetic induction principles
  • Familiarity with the formula for induced emf: |change in magnetic flux/change in time|
  • Knowledge of capacitor equations, specifically V = Q/C
  • Basic concepts of inductance and resistance in electrical circuits
NEXT STEPS
  • Research the calculation of induced emf in coils using Faraday's law of induction
  • Study the relationship between magnetic flux and induced voltage in capacitors
  • Explore the effects of resistance on the charging time of capacitors in circuits
  • Learn about the role of time in electromagnetic induction problems
USEFUL FOR

Students studying electromagnetism, electrical engineers, and anyone interested in understanding the principles of capacitors and inductors in magnetic fields.

ANON
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a coil of wire is connected to an uncharged capacitor in a magnetic field...

Homework Statement


A 10-turn coil of wire having a diameter of 1.0 cm and a resistance of 0.20 ohms is in a 1.0 mT magnetic field
with the coil oriented for maximum flux. The coil is connected to an uncharged 1.0 microFarad capacitor rather than to a current meter. The coil is quickly pulled out of the magnetic field. Afterward, what is the voltage across the capacitor?
Hint: Use I=dq/dt to relate the net change of flux to the amount of charge that flows to the capacitor.


Homework Equations


potential difference = -L dI/dt, where L is the inductance
magnetic field, B = Uo NI/l
total magnetic flux = N (magnetic field for each turn) = N (Area)(B) = (Uo N^2 A I) / l
I = V/R
induced emf = |change in magnetic flux/change in time|
V = Q/C

The Attempt at a Solution


Voltage across the capacitor initially is 0 V, since capacitor is uncharged.
I found the total flux to be 7.85 x 10^-7 Wb.
The changing flux induces an emf.

I'm really stuck here. Can someone please help me? Thanks :)
 
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ANON said:

Homework Statement


A 10-turn coil of wire having a diameter of 1.0 cm and a resistance of 0.20 ohms is in a 1.0 mT magnetic field
with the coil oriented for maximum flux. The coil is connected to an uncharged 1.0 microFarad capacitor rather than to a current meter. The coil is quickly pulled out of the magnetic field. Afterward, what is the voltage across the capacitor?
Hint: Use I=dq/dt to relate the net change of flux to the amount of charge that flows to the capacitor.

Homework Equations


potential difference = -L dI/dt, where L is the inductance
magnetic field, B = Uo NI/l
total magnetic flux = N (magnetic field for each turn) = N (Area)(B) = (Uo N^2 A I) / l
I = V/R
induced emf = |change in magnetic flux/change in time|
V = Q/C

The Attempt at a Solution


Voltage across the capacitor initially is 0 V, since capacitor is uncharged.
I found the total flux to be 7.85 x 10^-7 Wb.
The changing flux induces an emf.

I'm really stuck here. Can someone please help me? Thanks :)
no time is given? if you're given a time then you have \frac{d\phi _B}{dt} and a voltage
 
No time is given.
 

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