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A container holds 8.0kg of water at 25degC...

  1. Jun 23, 2015 #1
    1. The problem statement, all variables and given/known data
    how much energy must be added to the water to create 2.0 kg of steam?

    2. Relevant equations


    3. The attempt at a solution
    I have no idea how im supposed to figure the answer out. what formulas do I use?
     
  2. jcsd
  3. Jun 23, 2015 #2
    What formula do you know that is related to heating and/or transforming material from one physical state to another? Those are the two processes which must occur here.
     
  4. Jun 23, 2015 #3
    q=mLv
     
  5. Jun 23, 2015 #4
    i attempted the answer:

    Q total=mcwΔt+msLf
    =8.0kg*4200j/kg*(100°C-25°C)+2.0kg*2.3*106
    =7.12*106J
     
  6. Jun 23, 2015 #5

    haruspex

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    Yes.
    If you want to make your working letter-perfect, include all units: 8.0kg*4200J/kg/°C*(100°C-25°C)+2.0kg*2.3*106J/kg.
     
  7. Jun 24, 2015 #6
    awesome! thanks for the help!
     
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