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Introductory Physics Homework Help
Understanding a Converging Lens and Its Two Positions
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[QUOTE="aeroboi, post: 6252431, member: 669024"] [B]Homework Statement:[/B] The distance between an object and its image is fixed at 40.0 cm. A converging lens of focal length f = 8.96 cm forms a sharp image for two positions of the lens. What is the distance between these two positions? [B]Relevant Equations:[/B] f=(s*s')/(s+s') s'=(sf)/(s-f) I am aware that the object would be to the left of the lens and the image would be to the right, but I don't understand what it is mean by " A converging lens of focal length f = 8.96 cm forms a sharp image for two positions of the lens." I don't understand where the two positions would be and why two positions are produced. I'd appreciate any help visualizing this and a push for an approach. Thanks! [/QUOTE]
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Introductory Physics Homework Help
Understanding a Converging Lens and Its Two Positions
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