A couple basic physics questions(vector sum and kinematics)

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SUMMARY

The discussion focuses on solving two physics problems involving kinematics and vector addition. For the first problem, the position of a particle is given by the equation x=(24t-2.0t³) m, and the particle is at the origin when t=2 seconds, resulting in a distance of 32 meters from the origin. The second problem involves vector B, which, when added to vector C (3i + 4j), results in a vector that has a magnitude equal to vector C and points in the positive y-direction; the magnitude of vector B is determined to be 3.2 m.

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Crusaderking1
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Homework Statement



I already know the answers because this is a review sheet, but I don't understand how to solve number 1, and I don't understand the wording of number 2.

1) A particle is moving along the x-axis and has a position given by x=(24t-2.0t3)m, where t is in seconds. How far is the particle from the origin (x=0) at the time when the particle is not moving.

answer is t=32 seconds, but I don't quite know how to solve for t this way.

2) A vector B, when added to vector C= 3i + 4j yields a resultant vector which is in the positive y-direction and has a magnitude equal to that of vector C. What is the magnitude of B?

I know how to add vectors, but I don't understand the wording here.

Answer is 3.2 m.
Thanks.
 
Physics news on Phys.org
1) When the particle is not moving, what is its velocity?

2) Assume vector B = xi + yj. |B+C| = |C| and the i-component of B+C is zero.
 
SteamKing said:
1) When the particle is not moving, what is its velocity?

2) Assume vector B = xi + yj. |B+C| = |C| and the i-component of B+C is zero.

1) It is 0. when v=0, t=2, when t=2, m=32 m.

2) crystal clear. thanks.
 
Last edited:

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