How do masses affect the acceleration of the center of mass?

Click For Summary
SUMMARY

The discussion focuses on calculating the acceleration of the center of mass for two particles with given vector positions in the xy plane. The first particle has a mass of 4.00 g and follows the position equation \( \mathbf{r}_1 = (3\mathbf{i} + 3\mathbf{j})t + 2\mathbf{j}t^2 \), while the second particle has a mass of 5.95 g with the position equation \( \mathbf{r}_2 = 3\mathbf{i} - 2\mathbf{i}t^2 - 6\mathbf{j}t \). The correct method involves considering the masses in the calculation of the center of mass and its acceleration, which was initially overlooked by the participants.

PREREQUISITES
  • Understanding of vector calculus and derivatives
  • Knowledge of Newton's laws of motion
  • Familiarity with the concept of center of mass
  • Basic principles of kinematics in two dimensions
NEXT STEPS
  • Study the derivation of the center of mass formula for multiple particles
  • Learn how to apply Newton's second law to systems of particles
  • Explore the implications of mass distribution on acceleration
  • Investigate the use of vector calculus in physics problems
USEFUL FOR

Students in physics, particularly those studying mechanics, as well as educators and tutors looking to clarify concepts related to center of mass and particle motion.

Kump
Messages
1
Reaction score
0

Homework Statement



The vector position of a 4.00 g particle moving in the xy plane varies in time according to
rarrowbold.gif
1 = (3i+3j)t +2jt^2
where t is in seconds and
rarrowbold.gif
is in centimeters. At the same time, the vector position of a 5.95 g particle varies as
rarrowbold.gif
2 = 3î − 2ît^2 − 6ĵt.
Determine the acceleration of the center of mass at t = 2.40.

Homework Equations

The Attempt at a Solution


A=-4i+4j
i took the second derivative of position to give me acceleration. This resulted in -4i+4j which is wrong[/B]
 

Attachments

  • rarrowbold.gif
    rarrowbold.gif
    70 bytes · Views: 588
  • rarrowbold.gif
    rarrowbold.gif
    70 bytes · Views: 720
  • rarrowbold.gif
    rarrowbold.gif
    70 bytes · Views: 743
Last edited:
Physics news on Phys.org
Can you show the details of how you arrived at your solution? Helpers won't simply confirm or deny a solution without work shown.
 
Kump said:

Homework Statement



The vector position of a 4.00 g particle moving in the xy plane varies in time according to
View attachment 2326741 = (3i+3j)t +2jt^2
where t is in seconds and View attachment 232675 is in centimeters. At the same time, the vector position of a 5.95 g particle varies as
View attachment 2326762 = 3î − 2ît^2 − 6ĵt.
Determine the acceleration of the center of mass at t = 2.40.

Homework Equations

The Attempt at a Solution


A=-4i+4j
i took the second derivative of position to give me acceleration. This resulted in -4i+4j which is wrong[/B]
You ignored the masses. How is the position of the center of mass defined?
 

Similar threads

Replies
7
Views
2K
  • · Replies 25 ·
Replies
25
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
Replies
5
Views
3K
Replies
1
Views
1K
  • · Replies 8 ·
Replies
8
Views
6K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K