A cube of side L=2 m is made of a cooper cable with 2mm^2

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SUMMARY

The discussion focuses on calculating the electric resistance of a cube made from copper cable with a side length of 2 meters and a cross-sectional area of 2 mm². The resistance of one side of the cube is determined using the formula R = ρL/A, resulting in an approximate resistance of 0.0172 Ω. The user expresses confusion regarding the calculation of equivalent resistance between points A and B, suggesting the need to consider the symmetry of the cube and the distribution of current across its edges.

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  • Understanding of electrical resistivity and resistance calculations
  • Familiarity with the formula R = ρL/A
  • Basic knowledge of electrical circuits and current flow
  • Concept of symmetry in electrical networks
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GaussianSurface

Homework Statement


A cube of side L=2m is made of a cooper cable with 2mm^2 of cross section area.
1) Find the electric resistance of one side of the cube.
2) Find the equivalent resistance in between the points A and B.
 

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Actualization: I've done the first statement. By doing this:
The electrical resistivity is defined with the formula R=ρL/A where ρ is the resistivity of the material measured in Ω*m, L is the length in meters and A is the Area measured in m^2.
So that it is:
L=2m
R=?
A=2mm²=2*10^-6m²
ρ= 1.72*10^-8
Replacing these terms in the formula is equal to ≈ 0.0172Ω
I got the first one but the second one I still confused.
 
GaussianSurface said:
the second one I still confused.
You can make good use of the symmetry.
Suppose you apply some voltage across A and B and a current I flows in one of the edges out of A. What current flows along the other edges out of A? What about the six edges those three edges lead to?
 

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