# A Difficult Equation

1. Jul 2, 2004

### Poweranimals

http://ourworld.cs.com/SuperSamuraiStar/math05.jpg [Broken]

Last edited by a moderator: May 1, 2017
2. Jul 2, 2004

### mathman

I tried your link. I didn't get any equation, just some fraction. Maybe the link is defective.

3. Jul 2, 2004

### Poweranimals

Okay, so it is a fraction, but how do I simplify it.

These are the options?

http://ourworld.cs.com/SuperSamuraiStar/math05b.jpg [Broken]

Last edited by a moderator: May 1, 2017
4. Jul 2, 2004

### styler

you want to multiply the numerator by the reciprocal of the denominator.
To do that, begin by writing the number 1 as the ratio of (x - 2) to its self.
That is , writing
1 = (x - 2) / (x - 2) in the first term

and

1 = (x + 2) / (x + 2) in the second term

will help a lot.

Last edited: Jul 2, 2004
5. Jul 2, 2004

### Poweranimals

Thanks.

This is a tricky one: http://ourworld.cs.com/SuperSamuraiStar/math15.jpg [Broken]

Last edited by a moderator: May 1, 2017
6. Jul 2, 2004

### fourier jr

I got (z^2)/(9x^8)

Last edited by a moderator: May 1, 2017
7. Aug 3, 2004

### Gaz031

For the latter one:
Just multiply it by itself, simplify that by collecting coefficients if you can, then put it beneath a one.
You could then simplify or express as a partial fraction as necessary.