(adsbygoogle = window.adsbygoogle || []).push({}); A uniform ladder of length 9 m leans against a frictionless vertical wall making an angle of 47° with the ground. The coefficient of static friction between the ladder and the ground is 0.41. If your mass is 74 kg and the ladder's mass is 33 kg, how far up the ladder can you climb before it begins to slip?

[tex]\Sigma F_x=0[/tex]

[tex]f_s-F_1 =0[/tex]

[tex]f_s=F_1[/tex]

[tex]\Sigma F_y=0[/tex]

[tex]w-F_n =0[/tex]

[tex]w=F_n[/tex]

Where [tex]F_1[/tex] is the natural force of the frictionless wall on the ladder, [tex]F_n[/tex] is the natural force of the floor on the ladder, and [tex]w[/tex] is the weight of the ladder.

[tex]\Sigma \tau =0[/tex]

[tex]F_1(sin\theta L)-w(\frac{cos\theta L}{2})=0[/tex]

Solving for [tex]F_1[/tex] gives you [tex]f_s[/tex]

I just don't know how to put this together and answer the question. The torque part is also probably wrong. Any advice would be appreciated.

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# Homework Help: A ladder against a frictionless wall

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