A little clarification on absolute values

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SUMMARY

The discussion centers on proving that the second-order ordinary differential equation (ODE) of the simple pendulum, represented as y'' = -(g/l)sin(y), is Lipschitz continuous using the norm 1. The key assertion is whether the inequality |sin(u) - sin(v)| ≤ |u - v| holds for all values of u and v. A participant confirms that this can be demonstrated using the Mean Value Theorem (MVT), establishing the Lipschitz condition for the sine function in this context.

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  • Knowledge of the Mean Value Theorem (MVT)
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relinquished™
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Hello again. I have a (stupid, but I'm not real sure about the answer-type) question. I'm trying to prove that the second order ODE of the simple pendulum y''=-(g/l)sin y is Lipschitz (using norm 1). After doing some evaluating, I came up with

<br /> |u&#039;-v&#039;| + |\frac{g}{l}||\sin u - \sin v|<br />

All I'm asking is if this is true for all values of u and v:

<br /> |\sin u - \sin v| \leq |u - v|<br />

All clarifications are appreciated.

Thanks,

Reli~
 
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I think you can show that |sin(u)-sin(v)| <= |u-v| using the MVT.
 

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