A microwave oven of mass 13.0kg is pushed a distance 8.80m up a ramp

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SUMMARY

The discussion focuses on calculating work done on a microwave oven of mass 13.0 kg pushed up a ramp over a distance of 8.80 m, considering the effects of friction. Participants debate whether to use the work-energy principle, specifically the equation W = change in KE, or to account for gravitational potential energy changes alongside frictional work. It is established that friction acts negatively, reducing the net work done on the system, thus decreasing the kinetic energy of the microwave oven as it ascends the ramp.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with the work-energy theorem
  • Knowledge of gravitational potential energy calculations
  • Basic concepts of friction and its effects on motion
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  • Study the work-energy principle in detail
  • Learn about calculating gravitational potential energy changes
  • Explore the effects of friction on kinetic energy in various scenarios
  • Investigate the application of free-body diagrams in analyzing forces on inclined planes
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Students in physics, educators teaching mechanics, and anyone interested in understanding the dynamics of objects on inclined planes with friction.

nouvelague
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Homework Statement
A microwave oven of mass 13.0 kg
is pushed a distance 8.80 m
up the sloping surface of a loading ramp inclined at an angle of 38.3 ∘
above the horizontal, by a constant force F⃗
with a magnitude 150 N
and acting parallel to the ramp. The coefficient of kinetic friction between the oven and the ramp is 0.240.


Part D
Use your answers to parts (A), (B), and (C) to calculate the increase in the oven's kinetic energy.
Take the free fall acceleration to be 9.80 m/s2
. Express your answer using two significant figures.
Relevant Equations
W = change in KE
-change in U + Wfriction = change in KE
For this one, am i supposed to use W = change in KE where i calculate work as ((F - friction - mgsintheta) times d), or am i supposed to do the change in -mgh plus Wfriction = change in KE (where if it is in this case, is the friction going to be a negative number?)
 
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Since friction is involved, you are supposed to use the kinetic energy theorem $$\Delta (KE)=W_{\text{net}}.$$ I assume that in the previous parts you have calculated all the works that are needed.
 
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nouvelague said:
where if it is in this case, is the friction going to be a negative number?
Will the friction occurring here increase or decrease the kinetic energy?
 

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