A particle motion problem in the x-y plane with constant acceleration

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haruspex said:
The acceleration is constant. What familiar path results from constant acceleration?
Since the position vector is quadratic so it will be a parabolic path.
Idk about constant acceleration path.
 
haruspex said:
What planet are you on?
Not linear
 
rudransh verma said:
Since the position vector is quadratic so it will be a parabolic path.
Idk about constant acceleration path.
In this case: is the position vector quadratic?
In this case: is acceleration constant?
In the general case: if acceleration is constant, will the position vector be quadratic?

If a ball is thrown in vacuum with constant gravity, its trajectory is parabolic, yes?
If you rotate the coordinate system, is its trajectory still parabolic?
 
haruspex said:
Sure.
To get the scalar eqns from the vector, take the dot product with, respectively, ##\hat x, \hat y##.
Conversely, multiply the scalar equns by respectively, ##\hat x, \hat y##, and add them to produce the vector equn.
Still working on latex
 

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