Well ... I'd start with that even if I did suggest it myself.The thing is that i dont care much for the answer, I want help on starting the problem so I can work it on my own. Would you mind pointing me in the right direction please?
OK it's good knowing that momentum is conserved and perhaps you will need that elsewhere on your exam. But ... not on this problem.I have been working on it, I've been stuck on the damn problem for 3 days now, I know that energy and momentum are conserved, but I cant seem to translate that into actual equations : /
Edit: ok i think im getting somewhere.
I know that the point where the particle leaves is = 0, so mgcosx-ma=0 right?
So Cosx = a/g
Also Etot = Ekin + Epot= .5mv^2 - mgh= 0
=====> v^2= 2gh
But im stuck in a loop now haha
Part of the problem with that equation is that 2 of those terms are Force, the other energy.Ok so this is independent of the mass of the penny and of g. So would i have
mgcosx= mgh + mv^2/R??
Since V is, as you found, a function of h, and so is θ ...Gotcha so it would only be
mgcosx= mv^2/R? But what would i solve for?
Even better then eh?... Cosx= 2h/r. But how is theta a function of h??
For one thing it's not 2h/r.Yeah but with what? what can i substitute cosx with?
That's almost right.Ok lets see now, so Cosx= a/g
a= v^2/R
So Cosx= a/g = v^2/ Rg = 2h/R
Ok and Cosx=R-h/R
So R-h/R = 2h/R
thats what I could figure out, but i need to figure out the angle when it drops off the sphere
Yes. But you need to eliminate h. Or eliminating R works too.Oh ok yeah im solving for Cosx=(R-h)/R
So wouldnt the angle be arcCos of (R-h)/R?