A problem in Trigonometry (Properties of Triangles)

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In any triangle ABC, prove that $$(b+c-a) \left( \cot {\frac {B}{2}} + \cot {\frac {C}{2}} \right)=2a \cot {\frac {A}{2}} $$
 
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Wrichik Basu said:
In any triangle ABC, prove that $$(b+c-a) \left( \cot {\frac {B}{2}} + \cot {\frac {C}{2}} \right)=2a \cot {\frac {A}{2}} $$

Did you try to solve this ?
Also you should not vandalise the template.
 
Buffu said:
Did you try to solve this ?
Also you should not vandalise the template.

I tried in several ways, trying to change a, b, c to 2R sin A and like that, or trying the formulae for cot A/2, but got nowhere.
 
Wrichik Basu said:
I tried in several ways, trying to change a, b, c to 2R sin A and like that, or trying the formulae for cot A/2, but got nowhere.
Use sine rule and A + B + C = 180.