1. The problem statement, all variables and given/known data see this link http://i45.tinypic.com/10gwhw2.jpg 2. Relevant equations F=kx, F=ma 3. The attempt at a solution ok first I find the total length of the pulley system, 2Sa+Sb=L, differentiating with respect to time i get, 2Va + VB=0 and thus 2Aa+Ab =0 So Aa =-Ab/2 next I first analyze block A and do a force balance to get, -Ma*g - k*x + 2T = Ma*Aa following this i analyze Block B doing a force balance again, T-Mb*g = Mb*Ab so to eliminate one of the variables I input Aa=-Ab/2 into the equation describing block A. I get -Ma*g-k*x+2T+Ma(-Ab/2) then i get -2(Ma*g-k*X+2T)=Ab so now i substitute this in Block B with real values T-98.1=10(19.62-400+2T) so T = 195.04 then Ab = 19.62-400+2(195.04) = 9.7 m/s^2 So now I have (delta)y = 0.5 m A=9.7 using the following equation i can solve for t, Δy=(1/2)at^(2) doing so i get 0.32s thus v = at = 9.7(0.32) =3.104 m/s However i do not have a solution for this exercise and unsure if my attempt is correct or not. Any help is greatly appreciated thanks!