Why is the Charge Density Calculation Incorrect?

[wf198349]

1. Homework Statement [/b]

A static charge distribution produces radial electric field as follows:

\stackrel{\rightarrow}{E}=A\frac{e^{-br}}{r}\stackrel{\rightarrow}{e_{r}}

A,b are constants,please compute the charge density.

Homework Equations

\nabla\cdot \stackrel{\rightarrow}{E}=\frac{\rho}{\epsilon}

The Attempt at a Solution

\nabla\cdot \stackrel{\rightarrow}{E}=\frac{1}{r^{2}}\frac{ \partial}{\partial r}(r^{2}A\frac{e^{-br}}{r})=\frac{1}{r^{2}}\frac{\partial}{\partial r}(Are^{-br})

But the result is wrong.Can you tell me why?

 

[wf198349]

1. Homework Statement [/b]

A static charge distribution produces radial electric field as follows:

\stackrel{\rightarrow}{E}=A\frac{e^{-br}}{r}\stackrel{\rightarrow}{e_{r}}

A,b are constants,please compute the charge density.

Homework Equations

\nabla\cdot \stackrel{\rightarrow}{E}=\frac{\rho}{\epsilon}

The Attempt at a Solution

\nabla\cdot \stackrel{\rightarrow}{E}=\frac{1}{r^{2}}\frac{ \partial}{\partial r}(r^{2}A\frac{e^{-br}}{r})=\frac{1}{r^{2}}\frac{\partial}{\partial r}(Are^{-br})

But the result is wrong.Can you tell me why?

 

[vela]

What result did you get and what did you expect?

 

[wf198349]

The reference answer is

\rho=\epsilon_{0}\nabla\cdot \stackrel{\rightarrow}{E}=-\frac{\epsilon_{0}Ab}{r^{2}}e^{-br}+4\pi\epsilon_{0}A\delta(r)

 

[vela]

It looks like there's a typo in the expression for the electric field. I think it should be
\mathbf{E} = \frac{Ae^{-br}}{r^2}\mathbf{e}_r

 

[wf198349]

But how can I get the term 4\pi\epsilon_{0}A\delta(r) ?

 

[vela]

Apply the integral form of Gauss's law using a sphere of radius r as the Gaussian surface and take the limit as r goes to 0. From that result, you should be able to deduce a point charge has to reside at the origin.