A question about Alice and Bob in SR

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SUMMARY

The discussion centers on the relativistic scenario involving Alice and Bob, where Bob remains stationary in Minkowski space while Alice moves with constant proper acceleration. The key equations governing their interactions are Alice's trajectory, described by ##X(\tau)=\frac{1}{a}\cosh(a\tau)## and ##T(\tau)=\frac{1}{a}\sinh(a\tau)##. The participants clarify how to compute the times shown on their watches when they meet again and the number of pulses Alice receives from Bob. The correct answers are: Alice's watch shows ##\tau = \frac{1}{a}\sinh^{-1}(aL)##, Bob's watch shows ##2\sqrt{L^2 - \frac{1}{a^2}}##, and Alice receives a number of pulses equal to the time interval divided by ##\Delta t##.

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  • #31
Ibix said:
It is. But whose time interval? Alice and Bob don't agree on the duration.

When answering the question, think whose clock is responsible for measuring ##\Delta t##.
Bob's, because ##\Delta t## is according to his clock.

So if I am not mistaken the number of pulses arriving to Alice are: ##(2/a\Delta t)\sqrt{L^2-1/a^2}##.
 
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  • #32
MathematicalPhysicist said:
Bob's, because ##\Delta t## is according to his clock.

So if I am not mistaken the number of pulses arriving to Alice are: ##(2/a\Delta t)\sqrt{L^2-1/a^2}##.
Exactly - the same number as emitted.
 
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