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A question in the energy of a capacitor

  1. Apr 7, 2013 #1
    The energy stored in a capacitor is defined as the amount of work required to charge it. Can anyone clarify to me who does this work? It sure must be opposite to the electric field. In the derivation why is it ∫ v dq ... I don't get this integral. Why isn't it negative?? Thanks!
     
  2. jcsd
  3. Apr 7, 2013 #2

    Drakkith

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    Staff: Mentor

    Why do you think it should be negative?
     
  4. Apr 7, 2013 #3
    The battery is doing work. Vdq is the infinitesimally small amount of energy dU stored.
     
  5. Apr 7, 2013 #4
    So is it because potential energy is the work done by an external force?.. I think I got it.. But why is it V dq and not for example Q dv?
     
  6. Apr 7, 2013 #5
    Why don't we make something like integral of dq*dv ???
     
  7. Apr 7, 2013 #6

    BruceW

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    Homework Helper

    Here's my understanding of it: We have for the voltage across a capacitor:
    [tex]V = \frac{q}{c} [/tex]
    And the equation for the power being spent, being turned into energy (stored in the capacitor) is:
    [tex]P = IV[/tex]
    Now, integrate both sides with respect to time, on the left hand side we get the energy stored in the capacitor, and on the right hand side, we get:
    [tex] \int V I dt [/tex]
    and since I = dq/dt that means our equation equals:
    [tex] \int V dq [/tex]
    You could instead write Q dV But usually in problems, we are told what the final charge on the capacitor is, so we want our limits to involve charge, not voltage.
     
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