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- Thread starter funginator
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alxm

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Or put it this way: A wave function which is a superposition of several eigenstates for several particles that does

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Or put it this way: A wave function which is a superposition of several eigenstates for several particles that doesnotgive a zero probability of finding two particles in the same state, simply isn't a valid solution to the Schrödinger equation for fermions.

I wonder if you mean that it's technically a valid solution of the differential equation but we have to throw it out because it violates the exclusion principle?

For example, if we take the ground state solution of the hydrogen atom and multiply it by any number greater than 1, then the resulting wave function is still a solution of the differential equation. We throw it out because it's not normalized, but it's still a valid solution of the differential equation.

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