A question on heat transfer and blackbodys

  • Thread starter pastro
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  • #1
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Main Question or Discussion Point

Hello,

I was wondering:
[tex]\frac{dQ}{dt}[/tex] = \sigma A T^{4}
for a perfect blackbody.

Also
Q = mc\DeltaT

If I take the time derivative of the above equation, set it equal to the power emitted by a blackbody, and solve the resulting differential equation for temperature, does that give me the temperature with which a blackbody radiator of a given mass and material cools in vacuum as a function of time???

Just curious...

Thanks!
 
Last edited:

Answers and Replies

  • #2
1,341
3
Ummm, I doubt it.

Equation 1 is for, well, radiation.

Equation 2, as I understand it, is for convective heat transfer.

The two are not really the same thing.
 

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