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A question on heat transfer and blackbodys

  1. Jun 25, 2010 #1

    I was wondering:
    [tex]\frac{dQ}{dt}[/tex] = \sigma A T^{4}
    for a perfect blackbody.

    Q = mc\DeltaT

    If I take the time derivative of the above equation, set it equal to the power emitted by a blackbody, and solve the resulting differential equation for temperature, does that give me the temperature with which a blackbody radiator of a given mass and material cools in vacuum as a function of time???

    Just curious...

    Last edited: Jun 25, 2010
  2. jcsd
  3. Jun 26, 2010 #2
    Ummm, I doubt it.

    Equation 1 is for, well, radiation.

    Equation 2, as I understand it, is for convective heat transfer.

    The two are not really the same thing.
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