- #1

- 15

- 0

## Main Question or Discussion Point

Hello,

I was wondering:

[tex]\frac{dQ}{dt}[/tex] = \sigma A T^{4}

for a perfect blackbody.

Also

Q = mc\DeltaT

If I take the time derivative of the above equation, set it equal to the power emitted by a blackbody, and solve the resulting differential equation for temperature, does that give me the temperature with which a blackbody radiator of a given mass and material cools in vacuum as a function of time???

Just curious...

Thanks!

I was wondering:

[tex]\frac{dQ}{dt}[/tex] = \sigma A T^{4}

for a perfect blackbody.

Also

Q = mc\DeltaT

If I take the time derivative of the above equation, set it equal to the power emitted by a blackbody, and solve the resulting differential equation for temperature, does that give me the temperature with which a blackbody radiator of a given mass and material cools in vacuum as a function of time???

Just curious...

Thanks!

Last edited: