# A question on heat transfer and blackbodys

1. Jun 25, 2010

### pastro

Hello,

I was wondering:
$$\frac{dQ}{dt}$$ = \sigma A T^{4}
for a perfect blackbody.

Also
Q = mc\DeltaT

If I take the time derivative of the above equation, set it equal to the power emitted by a blackbody, and solve the resulting differential equation for temperature, does that give me the temperature with which a blackbody radiator of a given mass and material cools in vacuum as a function of time???

Just curious...

Thanks!

Last edited: Jun 25, 2010
2. Jun 26, 2010

### Feldoh

Ummm, I doubt it.

Equation 1 is for, well, radiation.

Equation 2, as I understand it, is for convective heat transfer.

The two are not really the same thing.