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A rather simple DE

  1. Oct 29, 2006 #1
    Given that y' = [x(x^2+1)^1/2]/ye^y
    How do you find solve the differential equation?
    I got through some parts but have hard time solving for y when i got
    (y-1)e^y = [(x^2+1)^(3/2)]/3 + C

    Thanks a lot :)
    Last edited: Oct 29, 2006
  2. jcsd
  3. Oct 29, 2006 #2


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    It looks like you did a bit of a botch job on integrating the RHS.

    [tex]\int x^3 + xdx = x^4/4 + x^2/2[/tex]

    I don't think you can really go much farther than you have.

    EDIT: It looks right now. I would probably just hand it in as is, because I don't see a way to solve that
    Last edited: Oct 29, 2006
  4. Oct 29, 2006 #3
    My bad, it's actually y' = [x(x^2+1)^1/2]/ye^y, ;), posted the problem up wrong...

    Thanks anyway!
  5. Oct 31, 2006 #4
    if you want to give your professor something, you can isolate x in that problem, although you'll have a plus or minus in the solution..
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