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## Homework Statement

A 1209 kg safe is 1.54 m above a heavy-duty spring when the rope holding the safe breaks. Thr safe hits the spring and compress it 53 cm. What is he spring constant of the spring?

## Homework Equations

K=mV^2/2

U=mgh

Ki+Ui=Kf+Uf

## The Attempt at a Solution

I thought I understood momentuem and energy but not anymore. Here is what I did....

Ui=mgh= 2*9.8*1.54

Kf=mV^2/2

Then solved for V and got 5.494 m/s

Then used that velocity for the spring constant by using......

U=k(delta x)^2/2

K=mV^2/2

then solved for k and got 129912 N/m...... but that is coming up wrong what am i doing wrong.