(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A 1209 kg safe is 1.54 m above a heavy-duty spring when the rope holding the safe breaks. Thr safe hits the spring and compress it 53 cm. What is he spring constant of the spring?

2. Relevant equations

K=mV^2/2

U=mgh

Ki+Ui=Kf+Uf

3. The attempt at a solution

I thought I understood momentuem and energy but not anymore. Here is what I did....

Ui=mgh= 2*9.8*1.54

Kf=mV^2/2

Then solved for V and got 5.494 m/s

Then used that velocity for the spring constant by using......

U=k(delta x)^2/2

K=mV^2/2

then solved for k and got 129912 N/m...... but that is coming up wrong what am i doing wrong.

**Physics Forums - The Fusion of Science and Community**

# A safe held by a string breaks and lands on a spring

Know someone interested in this topic? Share a link to this question via email,
Google+,
Twitter, or
Facebook

- Similar discussions for: A safe held by a string breaks and lands on a spring

Loading...

**Physics Forums - The Fusion of Science and Community**