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i have the following non-homo differential equation.

[tex]y^{\prime\prime}+4y = 2~cos~x + 3x~sin~x[/tex]

[tex]\begin{cases} y(0) = 1 \\

y^{\prime}(0) = 2 \end{cases}[/tex]

Since there is a 3x term in front of sin x.

What is the form of the solution for this problem?

if it hadn't been there it probably would have been [tex]Asin~x + Bcos~x[/tex]

//James

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# Homework Help: A second order non homo differential equation

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