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**1. Homework Statement**

A city lot has the shape of a right triangle whose hypotehenuse is 7 ft longer that one of the other sides. Perimiter of the lot is 392 ft how long is each side.

**2. Homework Equations**

P = a + b +c = 392

hypothenuse is c^2 = a^2 + b^2

so if c is 7ft longer then one of the sides (let's say b)

then b +7 = c or b = c-7

a+ c-7 +c = 392

a +2c = 399

a = 399 -2c

To find c I use

Pythogorian formula but replace a and b with their equivalent of c

(399-2c)^2 + (c-7)^2 = c^2

Is it the right way to resolve the problem? if it is, why after 4-5 attempts I keep getting different values of c or sometimes no c at all :)

If it's the right way to go

is the (399-2c)^2 + (c-7)^2 = c^2 implies...

-4c^2 + 1596c + 159201 +c^2 - 14c + 49 = c^2 ? Just to make sure I'm not missing a minus.

Thank you:)

**3. The Attempt at a Solution**

**1. Homework Statement**

**2. Homework Equations**

**3. The Attempt at a Solution**