Solve Trig Problem: Horizontal Dist. Between Truck & Dock to Nearest Tenth

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Homework Help Overview

The problem involves a loading ramp connecting a loading dock and a tractor trailer, with specific heights and a length given. The objective is to determine the horizontal distance between the truck and the dock using trigonometric principles.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to apply the Pythagorean theorem to find the horizontal distance, introducing an imaginary hypotenuse. Some participants question the necessity of including the ground and suggest focusing solely on the ramp and the dock.

Discussion Status

Participants are exploring different interpretations of the problem setup. Some guidance has been provided regarding the application of the Pythagorean theorem, indicating that the original poster may have misapplied it in a non-right triangle context.

Contextual Notes

The original poster references a textbook answer that differs from their calculations, indicating a potential misunderstanding of the problem's geometric relationships.

Liam C
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Homework Statement


A loading ramp is 2.8m long. One end rests on a loading dock 0.7 meters above the ground, and the other end leads into the back of a a tractor trailer 1.2m above the ground. Find the horizontal distance between the back of the truck and the loading dock, to the nearest tenth of a meter.

Homework Equations


a² + b² = c²

The Attempt at a Solution


In order to solve this problem I figured out that you need to make an imaginary hypotenuse from the ground below the truck to the top of the loading dock. With that hypotenuse you need to figure out the horizontal distance between the back of the truck and the loading dock.
Attempt:
Let x represent the diagonal from the ground at the truck to the loading dock.
2.8^2 - .7^2 = x^2
√6.4 = √x^2
2.53m = x
That is for the imaginary hypotenuse. Now for the leg it asked for:
Let h represent the horizontal distance between the back of the truck to the start of the dock.
2.53^2 - .7^2 = h^2
6.4 - .49 = h^2
√5.91 = √h^2
2.43m = h
Then the therefor statement. The problem is, the textbook tells me the answer is 2.8. Where did I go wrong?
P.S
To get a mental image, just imagine a rectangle with a diagonal from the lower left corner to the upper right corner.
 
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What do you need the ground and this imaginary hypotenuse for? Have you drawn the situation?
 
fresh_42 said:
What do you need the ground and this imaginary hypotenuse for? Have you drawn the situation?
Yes, I have drawn it. You need the hypotenuse because the length it is asking me to solve requires it.
https://www.physicsforums.com/attachments/101935
math.png
 
Last edited by a moderator:
So you want to find ##h##. But ##h## can also be found at another place. This should simplify your calculation. Maybe you see it better, if you only think of the truck, the ramp and the dock. You don't need the ground.

Edit: Your error is that you apply Pythagoras on a triangle which isn't a right one.
 
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fresh_42 said:
So you want to find ##h##. But ##h## can also be found at another place. This should simplify your calculation. Maybe you see it better, if you only think of the truck, the ramp and the dock. You don't need the ground.

Edit: Your error is that you apply Pythagoras on a triangle which isn't a right one.
Ohhh, okay I think I can solve it from here, thank you.
 

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