A stream of protons and electrons

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SUMMARY

The discussion focuses on calculating the radius of curvature and direction of curvature for a stream of protons and electrons moving at a speed of 1.2 x 10^6 m/s in a magnetic field of 1.225 T. The relevant formula to use is the Lorentz force equation, which describes the force on a charged particle in a magnetic field. The radius of curvature can be determined using the formula r = mv/(qB), where m is mass, v is velocity, q is charge, and B is magnetic field strength. The direction of curvature for positive charges like protons is determined by the right-hand rule, indicating an upward curvature.

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  • Understanding of the Lorentz force equation
  • Knowledge of the right-hand rule for magnetic forces
  • Familiarity with the properties of protons and electrons
  • Basic concepts of circular motion in physics
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A stream of protons and electrons are shot horizontally (from the left edge of the page to the right) with a speed of 1.2 x 10^6 m/s. A magnetic field is oriented perpendicular to this motion (upward, out of the page) with a magnitude of 1.225 T.

What is the radius of the curvature and the direction for the curvature that each of these particles undergoes?

I do not know what formula/law that I need to use for this problem.

Any help would be appreciated!
 
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This is not Advanced Physics (read the sticky thread at the top of the Advanced Physics forum for clarification on this). Thread moved.

Have you tried looking up the law that describes the force experienced by a charged particle in a magnetic field? It should be in your notes or textbook.
 

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