(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

[tex]\int[/tex]sin^{3}cos^{2}xdx

3. The attempt at a solution

I've successfully solved this problem by factoring out 1 sinx and changing the sin^{2}x to (1-cos^{2}x then assigning u=cosx and du=-sinx and so on.

What I'm wondering is why does letting u=sin^{3}x in the original integral not work. Then du=3cos^{2}xdx and there is a cos^{2}x in the original integral. Why does this fail? Please and thank you :)

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# Homework Help: A trigonometric substitution problem

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