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E[itex]_{r}[/itex]=[itex]\sqrt{(m_{0}c^{2})^{2}+(pc)^{2}}[/itex]

Where E[itex]_{r}[/itex] is relativistic energy

and m[itex]_{0}[/itex] is rest mass

In the formula, what is p and what is (pc)[itex]^{2}[/itex]?

Also, does the relativistic energy calculated here becomes relativistic mass of the object using E=mc[itex]^{2}[/itex]?