Absorption Line's Different Wavelengths

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Homework Help Overview

The discussion revolves around the observation of an absorption line of hydrogen in the spectrum of a galaxy, comparing its wavelength observed at 494.9 nm to a laboratory measurement of 490 nm. Participants explore implications regarding the motion of the galaxy based on these wavelength differences.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the significance of the observed wavelength shift and its relation to the galaxy's motion, questioning whether the galaxy is moving towards or away from Earth. There are attempts to calculate the velocity based on the wavelength difference.

Discussion Status

The conversation includes various interpretations of the wavelength changes and their implications for the galaxy's movement. Some participants provide guidance on precision in calculations, while others seek clarification on the implications of their findings.

Contextual Notes

Participants mention that the problem is part of a long-distance learning course in GCSE Astronomy. There are discussions about the precision of calculations and the significance of the speed of light in the context of the problem.

Atominate
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Hey Guys. If an absorption line of hydrogen was observed in the spectrum of the Galaxy, and it's wavelength was 494.9nm, and then the same line was found to be 490nm in the laboratory (in orbit around Earth), what could be drawn from that?
Thanks,
Atominate
 
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What do you think?
Is this homework?
 
mfb said:
What do you think?
Is this homework?
I am doing a GCSE Astronomy course, but it's not for school. It is a long distance learning course, and this is a question on one of the assignments.

I know that the nm means the nanometers. From the nm of the absorption line, one can draw the temperature and radial velocity. To determine the velocity, one would:
(Observed Wavelength - True Wavelength) divided by the True Wavelength = v/c
(494.9 - 490) dived by 490 = 0.01
0.01 x 300000 (speed of light) = 3000
So we can say, that the Galaxy is blue shifted, and therefore coming towards us at a velocity of 3000 km/s?
 
I moved the thread to the homework section.

Does the wavelength get longer or shorter if the galaxy is moving towards us?

You might want to keep one more digit precision in the calculations.
 
mfb said:
I moved the thread to the homework section.
Does the wavelength get longer or shorter if the galaxy is moving towards us?
You might want to keep one more digit precision in the calculations.
Thanks for moving it to the more specific section. The wavelength would get shorter. What do you mean about the digit?
 
Atominate said:
The wavelength would get shorter.
But the wavelength you are given here gets longer.
Atominate said:
What do you mean about the digit?
Your rounding is quite imprecise.
 
I see, so the wavelength is increasing by 4.9nm meaning the Galaxy is moving away?

I've been told to consider the speed of light as 300,000km/s for this question. Is this what you mean about rounding?
 
Atominate said:
I see, so the wavelength is increasing by 4.9nm meaning the Galaxy is moving away?
Right.
Atominate said:
I've been told to consider the speed of light as 300,000km/s for this question. Is this what you mean about rounding?
No, that is fine. The 0.01 relative shift you calculated is imprecise. There is a huge difference between 0.005 and 0.0149 (a factor of 3!) but both would get rounded to 0.01 if you just keep two digits after the decimal point.
 
mfb said:
No, that is fine. The 0.01 relative shift you calculated is imprecise. There is a huge difference between 0.005 and 0.0149 (a factor of 3!) but both would get rounded to 0.01 if you just keep two digits after the decimal point.
I don't understand what you mean. I am not rounding any of the figures. Can you explain?
 
  • #10
Ah I see, it happens to be "exactly" 0.01. I would still keep one more digit and write it as 0.010.
 
  • #11
mfb said:
Ah I see, it happens to be "exactly" 0.01. I would still keep one more digit and write it as 0.010.
Okay. Thanks for your help.
 

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