- #1
Prashasti
- 63
- 2
In a purely capacitive ac circuit, we get,
Im = Vm*ω*C, ...(1)
Where, Im = Amplitude of the current
Vm = Amplitude of the voltage
Now, what I think is,
We know that in a purely capacitive circuit, voltage lags behind current by a phase difference of ∏/2 rad. So, at any time 't',
I = Im sin(ωt+∏/2)
V = Vm sinωt
Using Kirchhoff's Loop Rule,
V = Vmsinωt = q/C
Where q = charge on the capacitor at time 't',
To find the current, I = dq/dt,
dq = Idt,
q = ∫Idt
q = ∫Imcosωt dt
q = Im∫cosωt dt
q = Im*ω*sinωt
So, Vmsinωt = Im*ω*sinωt /C
Vm = Im*ω/C
Im = Vm*C/ω, which is apparently, not equal to equation (1).
Am I wrong in my approach?
Im = Vm*ω*C, ...(1)
Where, Im = Amplitude of the current
Vm = Amplitude of the voltage
Now, what I think is,
We know that in a purely capacitive circuit, voltage lags behind current by a phase difference of ∏/2 rad. So, at any time 't',
I = Im sin(ωt+∏/2)
V = Vm sinωt
Using Kirchhoff's Loop Rule,
V = Vmsinωt = q/C
Where q = charge on the capacitor at time 't',
To find the current, I = dq/dt,
dq = Idt,
q = ∫Idt
q = ∫Imcosωt dt
q = Im∫cosωt dt
q = Im*ω*sinωt
So, Vmsinωt = Im*ω*sinωt /C
Vm = Im*ω/C
Im = Vm*C/ω, which is apparently, not equal to equation (1).
Am I wrong in my approach?