AC circuit power formula question

AI Thread Summary
The discussion centers on the confusion surrounding the use of the formula P=I^2R for calculating power in an AC circuit. It highlights that the correct approach involves using the root mean square (Vrms) voltage and the impedance (Z) to find the current (Irms) with the equation I_{rms}=V_{rms}/Z. The power factor is also mentioned but deemed unnecessary for this specific calculation. The resistance (R) is clarified to be 75Ω, while the impedance (Z) is 105Ω. Overall, the correct method for calculating average power in this AC circuit is emphasized, leading to the answer of 43.5 W.
bluesteels
Messages
28
Reaction score
1
Homework Statement
An L-R-C series circuit is connected to a 120 Hz ac source
that has Vrms = 80.0 V. The circuit has a resistance of 75.0 Ω and an
impedance at this frequency of 105 Ω. What average power is delivered
to the circuit by the source?
Relevant Equations
P=I^2R
P= Irms * Vrms * Power factor
Power factor = R/Z
im kinda confused on why can't you just use the formula P=I^2R.

Can you just use Vrms or Vamp (not sure which one is it) and the value of R which is 105Ω to solve for I

Then just plug it in the formula P=I^2R. But when i did that it the wrong answer so is this formula don't work for AC circuit or am i missing something. The answer for the question is 43.5 W btw
 
Physics news on Phys.org
bluesteels said:
Homework Statement:: An L-R-C series circuit is connected to a 120 Hz ac source
that has Vrms = 80.0 V. The circuit has a resistance of 75.0 Ω and an
impedance at this frequency of 105 Ω. What average power is delivered
to the circuit by the source?
Relevant Equations:: P=I^2R
P= Irms * Vrms * Power factor
Power factor = R/Z

im kinda confused on why can't you just use the formula P=I^2R.
I think you just did it wrong, try again. Your words are good. I don't know what's wrong with your numbers.

But, a couple of ancillary comments:
1) I have no idea what Vamp means. That's OK, you do, plus probably the people in your community too. Most EEs would be left wondering what you're talking about. In my world the standard terms for voltages are Vdc = Vave, Vrms, Vac (which is Vrms plus the assumption the waveforms are sinusoidal), Vpk (the peak voltage of any waveform), and then just the generic V, which is confusing unless you know the context. All of these are different from v(t) because they represent scalar measurements, not a waveform or an instantaneous value.

2) I'm always a bit confused about what people mean when they talk about resistance and impedance in the same context. Some (electricians, mostly) think impedance refers to only the imaginary or reactive component. Which (according to me) is wrong, that would be reactance. Impedance means the real (resistive) plus the imaginary (reactive) portions. In this case they did it correctly, they mean |Z| = 105Ω and Re(Z)=75Ω.

3) I'd leave power factor out of this. It's kind of out of context this time.

Ask again if you're still confused. Show your work so we can see what's wrong.
 
This is rather simple but I think you are ... overthinking it. I ll just remind you the "easy" equation $$I_{rms}=\frac{V_{rms}}{Z}$$ and I think you can figure out the rest.

Also the value of R is 75 Ohm, the value of Z is 105 Ohm.
 
Thread 'Minimum mass of a block'
Here we know that if block B is going to move up or just be at the verge of moving up ##Mg \sin \theta ## will act downwards and maximum static friction will act downwards ## \mu Mg \cos \theta ## Now what im confused by is how will we know " how quickly" block B reaches its maximum static friction value without any numbers, the suggested solution says that when block A is at its maximum extension, then block B will start to move up but with a certain set of values couldn't block A reach...
TL;DR Summary: Find Electric field due to charges between 2 parallel infinite planes using Gauss law at any point Here's the diagram. We have a uniform p (rho) density of charges between 2 infinite planes in the cartesian coordinates system. I used a cube of thickness a that spans from z=-a/2 to z=a/2 as a Gaussian surface, each side of the cube has area A. I know that the field depends only on z since there is translational invariance in x and y directions because the planes are...
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'
Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is(Figure 2): F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
Back
Top