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Solving an AC Circuit Problem with R, L, C Values
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[QUOTE="gneill, post: 4972055, member: 293536"] Okay, that would make more sense. Try working with admittances rather than impedances. The admittance will have the same phase angle as the current since I = U*Y and U has only a real component. The math will still be nasty, but perhaps a bit less so. The admittance of the lone resistor branch is 1/R and purely real. The admittance of the inductor branch is -1/XL and purely imaginary (XL being the reactance). You should be able to write an expression for the admittance of the RC branch and split it into real and imaginary components without too much difficulty. After that the nastiness begins :nb) [/QUOTE]
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Solving an AC Circuit Problem with R, L, C Values
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