AC Circuits - peak to peak voltage

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SUMMARY

The discussion focuses on the calculation of peak-to-peak (Vpp) voltage in AC circuits, specifically for the sine wave represented by the equation V=2sin(2t) V. The peak-to-peak voltage is established as 4V for the full sine wave, but when the waveform is clipped below 0V, the effective peak-to-peak voltage becomes 2V. It is emphasized that this clipped waveform does not equate to a standard sine wave with a peak-to-peak voltage of 2V, as the root mean square (RMS) voltage differs significantly between the two signals.

PREREQUISITES
  • Understanding of sine wave equations and their properties
  • Knowledge of peak-to-peak voltage calculations
  • Familiarity with RMS voltage and its significance in AC circuits
  • Basic concepts of waveform clipping and its effects on voltage measurements
NEXT STEPS
  • Study the mathematical derivation of RMS voltage for different waveforms
  • Explore the effects of waveform clipping on signal integrity
  • Learn about AC circuit analysis techniques using tools like MATLAB or LTspice
  • Investigate the differences between various types of waveforms and their voltage characteristics
USEFUL FOR

Electrical engineers, students studying AC circuit theory, and professionals involved in signal processing or waveform analysis will benefit from this discussion.

pyroknife
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Let's say you have a sine wave V=2sin(2t) V. For this peak to peak voltage is 4V.
Then let's say that everything below V=0 is cut off.
Is the peak to peak value for this just from 0 to 2V? Making Vpp=2V?
 
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yeppp
 
pyroknife said:
Let's say you have a sine wave V=2sin(2t) V. For this peak to peak voltage is 4V.
Then let's say that everything below V=0 is cut off.
Is the peak to peak value for this just from 0 to 2V? Making Vpp=2V?

Yes, but it's not equivalent to a sine wave with 2V pk-pk = sin(2t). Not even if it's biased upwards so that V = 1 + sin(2t).
 
You are correct. pk-pk is exactly what it says, the difference between the maximum and minimum voltage. The v = 2sin(2t) signal cut off below 0 would have a pk-pk of 2 volts, but the rms voltage of this signal would be different from the rms voltage of the v =- sin(2t) signal. The rms voltage I am speaking of is the "root mean square" of tghe signal and is the effective power of the signal.
 

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