Calculate Load Angel & Pole Wheel Voltage Up

  • Thread starter Thread starter robax25
  • Start date Start date
  • Tags Tags
    Generator
Click For Summary
The discussion focuses on calculating the load angle and pole wheel voltage (Up) for a generator with a nominal power of 3 MVA and a nominal voltage of 3000 V. The initial calculation for current (I) was correct at 1000 A, but the subsequent calculation for Up was incorrect, leading to confusion about the voltage representation. It was clarified that UN represents the line-to-line voltage of 3000 V, and the phase voltage should be calculated as 3000 V divided by the square root of 3, resulting in approximately 1732 V. The discussion emphasizes the importance of understanding the system's three-wire configuration and the correct application of formulas related to power and voltage. Overall, accurate calculations and clarifications are crucial for determining the load angle and pole wheel voltage.
robax25
Messages
238
Reaction score
3
Nominal power PN= 3MVA
Nominal Voltage UN= 3000v (Y)
Line frequency f=50 Hz
Number of ole pairs= 2
Synchronous Reactance X1= 2.5 ohms

There is no reactive power and the generator can be assumed as lossless.

Please calculate Load angel and pole wheel voltage Up

Formula and my solution,
I=PN/UN
I=3MVA/3000V
I=1000AUN=XI +Up
Up= 3000v-2.5*1000A
UP=500v which is wrong

Load angel ? I don't know
 
Physics news on Phys.org
In my opinion UN=V;UP=E. See the attached sketch.
 

Attachments

  • Synchronous Generator Steady State.jpg
    Synchronous Generator Steady State.jpg
    36 KB · Views: 201
Sorry.Wrong sketch.
 

Attachments

  • Synchronous Generator Steady State.jpg
    Synchronous Generator Steady State.jpg
    37.7 KB · Views: 211
I am sorry. Two more parentheses are missing
 

Attachments

  • Synchronous Generator Steady State.jpg
    Synchronous Generator Steady State.jpg
    39.7 KB · Views: 230
I am not sure what does represent UN=3000V[Y]. Since it is about 50 Hz IEC Standard IEC 60038 Table 3 Note 1:
These systems are generally three-wire systems unless otherwise indicated. The values indicated are voltages between phases.
So, the voltage is 3 kV between phases. The power has to be: √3.I.UN.cos(ϕ). The voltage per phase it is then 3000/√3=1732 V
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
16K
Replies
1
Views
3K
Replies
1
Views
10K
  • · Replies 3 ·
Replies
3
Views
22K
  • · Replies 12 ·
Replies
12
Views
6K
  • · Replies 2 ·
Replies
2
Views
5K
  • · Replies 4 ·
Replies
4
Views
10K