AC Theory question with capacitors

[jami8337]

Three uncharged capacitors each of 1uF are connected in parallel and the combination connected to a 100V power supply via a 1MΩ resistor. After 2s the capacitors are removed, connected in series and the new combination allowed to discharge through a 10kΩ resistor.

Find the discharge current at the start of discharge and 3ms late


I was just thinking the general discharge equation:
q=q e^(-t/RC)


I have no idea where to go with it though so if anyone can point me in the right direction id be very grateful

 

[NascentOxygen]

• Voltages in series add together.

• Capacitances in series add according to: 1/C = 1/C1 + 1/C2 + ...

I was just thinking the general discharge equation:
q=q e^(-t/RC)

Yes, that's what you use. First for the capacitors charging, then for them discharging. R and C will differ for the charging and discharging situations.