Accelerating a Uniform Sphere Down an Incline

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SUMMARY

The discussion focuses on calculating the acceleration of the center of mass of a uniform sphere rolling down a 30-degree incline from a height h. The initial kinetic energy is expressed as K_i = mghsin30, while the final kinetic energy is K_f = 1/2mv^2 + 1/2Iω^2. The correct formula for the speed of the center of mass (CM) at the end of the slope is derived as v = √(10/7 * gh sin30). To find the acceleration of the CM, the relationship s = v^2/(2a) is utilized.

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physikx
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Homework Statement


A uniform sphere rolls down a 30 degree incline θ from height h. Initially, the solid is at rest. Find the acceleration for the center of the mass of the solid.

I am not sure where to start with this problem. I started with the energy formulas, but I am not sure how to find the acceleration of the center of mass from there. I just need a guide on what formulas or setup to use, thanks!

Homework Equations


Translational and rotational motion equations

The Attempt at a Solution


K_i=mghsin30
K_f=1/2mv^2+1/2Iω^2

then I solved for v:
v=radical(10/7*ghsin30)
 
Last edited:
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Hi, physikx,

The potential energy is mgh (h is the height of the (slope). Correct your result for v.

V is the speed of the CM at the end of the slope. Find the length travelled, and use the relation s=v^2/(2a) to determine the acceleration of the CM.

ehild
 
Hey ehid,

Thank you so much for the help! I was able to setup the problem and get the answer. I really appreciate the guidance.

Peace
 
You are welcome.

ehild
 

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